| Did you mean to convert | newton-meter newton-meter newton-metre |
to | foot-pound force foot-pound force |
How many n-m in 1 foot pound? The answer is 1.3558179483314. We assume you are converting between newton-metre and foot-pound force. You can view more details on each measurement unit: n-m or foot pound The SI derived unit for torque is the newton meter. 1 newton meter is equal to 1 n-m, or 0.73756214927727 foot pound. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between newton metres and foot pounds. Type in your own numbers in the form to convert the units!
1 n-m to foot pound = 0.73756 foot pound
5 n-m to foot pound = 3.68781 foot pound
10 n-m to foot pound = 7.37562 foot pound
20 n-m to foot pound = 14.75124 foot pound
30 n-m to foot pound = 22.12686 foot pound
40 n-m to foot pound = 29.50249 foot pound
50 n-m to foot pound = 36.87811 foot pound
75 n-m to foot pound = 55.31716 foot pound
100 n-m to foot pound = 73.75621 foot pound
You can do the reverse unit conversion from foot pound to n-m, or enter any two units below:
Newton metre is the unit of moment in the SI system. Its symbol is N m or N·m. It is a compound unit of torque corresponding to the torque from a force of 1 newton applied over a distance arm of 1 metre.
As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.
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