How many newton-metre in 1 foot pound?
The answer is 1.3558179483314.
We assume you are converting between newton-metre and foot-pound force.
You can view more details on each measurement unit: newton-metre or
foot pound
The SI derived unit for torque is the newton meter.
1 newton meter is equal to 1 newton-metre, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between newton metres and foot pounds.
Type in your own numbers in the form to convert the units!

››Quick conversion chart of newton-metre to foot pound

1 newton-metre to foot pound = 0.73756 foot pound

5 newton-metre to foot pound = 3.68781 foot pound

10 newton-metre to foot pound = 7.37562 foot pound

20 newton-metre to foot pound = 14.75124 foot pound

30 newton-metre to foot pound = 22.12686 foot pound

40 newton-metre to foot pound = 29.50249 foot pound

50 newton-metre to foot pound = 36.87811 foot pound

75 newton-metre to foot pound = 55.31716 foot pound

100 newton-metre to foot pound = 73.75621 foot pound

Newton metre is the unit of moment in the SI system. Its symbol is N m or N·m. It is a compound unit of torque corresponding to the torque from a force of 1 newton applied over a distance arm of 1 metre.

››Definition: Foot pound

As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.

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