| Did you mean to convert | foot-pound force foot-pound force |
to | newton-meter newton-meter newton-metre |
How many foot pound in 1 n-m? The answer is 0.73756214927727. We assume you are converting between foot-pound force and newton-meter. You can view more details on each measurement unit: foot pound or n-m The SI derived unit for torque is the newton meter. 1 foot pound is equal to 1.3558179483314 newton meter. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and newton meters. Type in your own numbers in the form to convert the units!
1 foot pound to n-m = 1.35582 n-m
5 foot pound to n-m = 6.77909 n-m
10 foot pound to n-m = 13.55818 n-m
15 foot pound to n-m = 20.33727 n-m
20 foot pound to n-m = 27.11636 n-m
25 foot pound to n-m = 33.89545 n-m
30 foot pound to n-m = 40.67454 n-m
40 foot pound to n-m = 54.23272 n-m
50 foot pound to n-m = 67.7909 n-m
You can do the reverse unit conversion from n-m to foot pound, or enter any two units below:
As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.
Newton metre is the unit of moment in the SI system. Its symbol is N m or N·m. It is a compound unit of torque corresponding to the torque from a force of 1 newton applied over a distance arm of 1 metre.
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