| Did you mean to convert | foot-pound force |
to | calorie [15 °C] calorie [I.T.] calorie [nutritional] calorie [thermochemical] |
How many foot-pound force in 1 cal? The answer is 3.0872876444448. We assume you are converting between foot-pound force and calorie [15 °C]. You can view more details on each measurement unit: foot-pound force or cal The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot-pound force, or 0.23890295761862 cal. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and calories. Type in your own numbers in the form to convert the units!
1 foot-pound force to cal = 0.32391 cal
5 foot-pound force to cal = 1.61954 cal
10 foot-pound force to cal = 3.23909 cal
20 foot-pound force to cal = 6.47818 cal
30 foot-pound force to cal = 9.71727 cal
40 foot-pound force to cal = 12.95636 cal
50 foot-pound force to cal = 16.19545 cal
75 foot-pound force to cal = 24.29317 cal
100 foot-pound force to cal = 32.39089 cal
You can do the reverse unit conversion from cal to foot-pound force, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
15 °C calorie: the amount of energy required to warm 1 g of air-free water from 14.5 °C to 15.5 °C at a constant pressure of 101.325 kPa (1 atm). Experimental values of this calorie ranged from 4.1852 J to 4.1858 J. The CIPM in 1950 published a mean experimental value of 4.1855 J, noting an uncertainty of 0.0005 J.
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