How many foot-pound force in 1 decajoule? The answer is 7.3756214927727. We assume you are converting between foot-pound force and decajoule. You can view more details on each measurement unit: foot-pound force or decajoule The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot-pound force, or 0.1 decajoule. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and decajoules. Type in your own numbers in the form to convert the units!
1 foot-pound force to decajoule = 0.13558 decajoule
5 foot-pound force to decajoule = 0.67791 decajoule
10 foot-pound force to decajoule = 1.35582 decajoule
20 foot-pound force to decajoule = 2.71164 decajoule
30 foot-pound force to decajoule = 4.06745 decajoule
40 foot-pound force to decajoule = 5.42327 decajoule
50 foot-pound force to decajoule = 6.77909 decajoule
75 foot-pound force to decajoule = 10.16863 decajoule
100 foot-pound force to decajoule = 13.55818 decajoule
You can do the reverse unit conversion from decajoule to foot-pound force, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "deca" represents a factor of 101, or in exponential notation, 1E1.
So 1 decajoule = 101 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
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