How many foot pound in 1 ergs? The answer is 7.3756214927727E-8. We assume you are converting between foot-pound force and erg. You can view more details on each measurement unit: foot pound or ergs The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot pound, or 10000000 ergs. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and ergs. Type in your own numbers in the form to convert the units!
1 foot pound to ergs = 13558179.48331 ergs
2 foot pound to ergs = 27116358.96663 ergs
3 foot pound to ergs = 40674538.44994 ergs
4 foot pound to ergs = 54232717.93326 ergs
5 foot pound to ergs = 67790897.41657 ergs
6 foot pound to ergs = 81349076.89988 ergs
7 foot pound to ergs = 94907256.3832 ergs
8 foot pound to ergs = 108465435.86651 ergs
9 foot pound to ergs = 122023615.34983 ergs
10 foot pound to ergs = 135581794.83314 ergs
You can do the reverse unit conversion from ergs to foot pound, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
An erg is the unit of energy and mechanical work in the centimetre-gram-second (CGS) system of units, symbol "erg". Its name is derived from the Greek word meaning "work".
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