How many foot pound in 1 megalerg?
The answer is 0.073756214927727.
We assume you are converting between foot-pound force and megalerg.
You can view more details on each measurement unit:
foot pound or
megalerg
The SI derived unit for energy is the joule.
1 joule is equal to 0.73756214927727 foot pound, or 10 megalerg.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between foot pounds and megalerg.
Type in your own numbers in the form to convert the units!
1 foot pound to megalerg = 13.55818 megalerg
2 foot pound to megalerg = 27.11636 megalerg
3 foot pound to megalerg = 40.67454 megalerg
4 foot pound to megalerg = 54.23272 megalerg
5 foot pound to megalerg = 67.7909 megalerg
6 foot pound to megalerg = 81.34908 megalerg
7 foot pound to megalerg = 94.90726 megalerg
8 foot pound to megalerg = 108.46544 megalerg
9 foot pound to megalerg = 122.02362 megalerg
10 foot pound to megalerg = 135.58179 megalerg
You can do the reverse unit conversion from megalerg to foot pound, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "mega" represents a factor of 106, or in exponential notation, 1E6.
So 1 megalerg = 106 lerg.
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