How many megalerg in 1 foot pound?
The answer is 13.558179483314.
We assume you are converting between megalerg and foot-pound force.
You can view more details on each measurement unit: megalerg or
foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 10 megalerg, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between megalerg and foot pounds.
Type in your own numbers in the form to convert the units!

››Quick conversion chart of megalerg to foot pound

1 megalerg to foot pound = 0.07376 foot pound

10 megalerg to foot pound = 0.73756 foot pound

20 megalerg to foot pound = 1.47512 foot pound

30 megalerg to foot pound = 2.21269 foot pound

40 megalerg to foot pound = 2.95025 foot pound

50 megalerg to foot pound = 3.68781 foot pound

100 megalerg to foot pound = 7.37562 foot pound

200 megalerg to foot pound = 14.75124 foot pound

››Want other units?

You can do the reverse unit conversion from
foot pound to megalerg, or enter any two units below:

The SI prefix "mega" represents a factor of
10^{6}, or in exponential notation, 1E6.

So 1 megalerg = 10^{6} lerg.

››Definition: Foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.

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