How many foot pound in 1 zettajoule?
The answer is 7.3756214927727E+20.
We assume you are converting between foot-pound force and zettajoule.
You can view more details on each measurement unit:
foot pound or zettajoule
The SI derived unit for energy is the joule.
1 joule is equal to 0.73756214927727 foot pound, or 1.0E-21 zettajoule.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between foot pounds and zettajoules.
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You can do the reverse unit conversion from zettajoule to foot pound, or enter any two units below:
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foot pound to megajoule
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "zetta" represents a factor of 1021, or in exponential notation, 1E21.
So 1 zettajoule = 1021 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
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