How many newton-centimeter in 1 foot pound?
The answer is 135.58179483314.
We assume you are converting between newton centimeter and foot-pound force.
You can view more details on each measurement unit:
newton-centimeter or foot pound
The SI derived unit for torque is the newton meter.
1 newton meter is equal to 100 newton-centimeter, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between newton centimeters and foot pounds.
Type in your own numbers in the form to convert the units!
1 newton-centimeter to foot pound = 0.00738 foot pound
10 newton-centimeter to foot pound = 0.07376 foot pound
50 newton-centimeter to foot pound = 0.36878 foot pound
100 newton-centimeter to foot pound = 0.73756 foot pound
200 newton-centimeter to foot pound = 1.47512 foot pound
500 newton-centimeter to foot pound = 3.68781 foot pound
1000 newton-centimeter to foot pound = 7.37562 foot pound
You can do the reverse unit conversion from foot pound to newton-centimeter, or enter any two units below:
newton-centimeter to newton meter
newton-centimeter to micronewton-meter
newton-centimeter to newton metre
newton-centimeter to ounce-inch
newton-centimeter to kilogram-centimeter
newton-centimeter to poundal-foot
newton-centimeter to gram-centimeter
newton-centimeter to ounce-foot
newton-centimeter to meganewton-meter
newton-centimeter to kilogram-meter
As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.
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