How many foot pound in 1 newton-centimeter? The answer is 0.0073756214927727. We assume you are converting between foot-pound force and newton centimeter. You can view more details on each measurement unit: foot pound or newton-centimeter The SI derived unit for torque is the newton meter. 1 newton meter is equal to 0.73756214927727 foot pound, or 100 newton-centimeter. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and newton centimeters. Type in your own numbers in the form to convert the units!
1 foot pound to newton-centimeter = 135.58179 newton-centimeter
2 foot pound to newton-centimeter = 271.16359 newton-centimeter
3 foot pound to newton-centimeter = 406.74538 newton-centimeter
4 foot pound to newton-centimeter = 542.32718 newton-centimeter
5 foot pound to newton-centimeter = 677.90897 newton-centimeter
6 foot pound to newton-centimeter = 813.49077 newton-centimeter
7 foot pound to newton-centimeter = 949.07256 newton-centimeter
8 foot pound to newton-centimeter = 1084.65436 newton-centimeter
9 foot pound to newton-centimeter = 1220.23615 newton-centimeter
10 foot pound to newton-centimeter = 1355.81795 newton-centimeter
You can do the reverse unit conversion from newton-centimeter to foot pound, or enter any two units below:
As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.
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