How many foot pounds in 1 decajoule? The answer is 7.3756214927727. We assume you are converting between foot-pound force and decajoule. You can view more details on each measurement unit: foot pounds or decajoule The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot pounds, or 0.1 decajoule. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and decajoules. Type in your own numbers in the form to convert the units!
1 foot pounds to decajoule = 0.13558 decajoule
5 foot pounds to decajoule = 0.67791 decajoule
10 foot pounds to decajoule = 1.35582 decajoule
20 foot pounds to decajoule = 2.71164 decajoule
30 foot pounds to decajoule = 4.06745 decajoule
40 foot pounds to decajoule = 5.42327 decajoule
50 foot pounds to decajoule = 6.77909 decajoule
75 foot pounds to decajoule = 10.16863 decajoule
100 foot pounds to decajoule = 13.55818 decajoule
You can do the reverse unit conversion from decajoule to foot pounds, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "deca" represents a factor of 101, or in exponential notation, 1E1.
So 1 decajoule = 101 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
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