How many foot pound in 1 kJ? The answer is 737.56214927727. We assume you are converting between foot-pound force and kilojoule. You can view more details on each measurement unit: foot pound or kJ The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot pound, or 0.001 kJ. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and kilojoules. Type in your own numbers in the form to convert the units!
1 foot pound to kJ = 0.00136 kJ
10 foot pound to kJ = 0.01356 kJ
50 foot pound to kJ = 0.06779 kJ
100 foot pound to kJ = 0.13558 kJ
200 foot pound to kJ = 0.27116 kJ
500 foot pound to kJ = 0.67791 kJ
1000 foot pound to kJ = 1.35582 kJ
You can do the reverse unit conversion from kJ to foot pound, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "kilo" represents a factor of 103, or in exponential notation, 1E3.
So 1 kilojoule = 103 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
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