How many foot pound in 1 kilogram-force meter?
The answer is 7.2330138512099.
We assume you are converting between foot-pound force and kilogram-force meter.
You can view more details on each measurement unit:
foot pound or
kilogram-force meter
The SI derived unit for energy is the joule.
1 joule is equal to 0.73756214927727 foot pound, or 0.10197162129779 kilogram-force meter.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between foot pounds and kilogram-force meter.
Type in your own numbers in the form to convert the units!
1 foot pound to kilogram-force meter = 0.13825 kilogram-force meter
5 foot pound to kilogram-force meter = 0.69127 kilogram-force meter
10 foot pound to kilogram-force meter = 1.38255 kilogram-force meter
20 foot pound to kilogram-force meter = 2.7651 kilogram-force meter
30 foot pound to kilogram-force meter = 4.14765 kilogram-force meter
40 foot pound to kilogram-force meter = 5.5302 kilogram-force meter
50 foot pound to kilogram-force meter = 6.91275 kilogram-force meter
75 foot pound to kilogram-force meter = 10.36912 kilogram-force meter
100 foot pound to kilogram-force meter = 13.8255 kilogram-force meter
You can do the reverse unit conversion from kilogram-force meter to foot pound, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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