How many foot pound in 1 exaattojoule? The answer is 0.73756214927727. We assume you are converting between foot-pound force and exaattojoule. You can view more details on each measurement unit: foot pound or exaattojoule The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot pound, or 1 exaattojoule. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and exaattojoules. Type in your own numbers in the form to convert the units!
1 foot pound to exaattojoule = 1.35582 exaattojoule
5 foot pound to exaattojoule = 6.77909 exaattojoule
10 foot pound to exaattojoule = 13.55818 exaattojoule
15 foot pound to exaattojoule = 20.33727 exaattojoule
20 foot pound to exaattojoule = 27.11636 exaattojoule
25 foot pound to exaattojoule = 33.89545 exaattojoule
30 foot pound to exaattojoule = 40.67454 exaattojoule
40 foot pound to exaattojoule = 54.23272 exaattojoule
50 foot pound to exaattojoule = 67.7909 exaattojoule
You can do the reverse unit conversion from exaattojoule to foot pound, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "exa" represents a factor of 1018, or in exponential notation, 1E18.
So 1 exaattojoule = 1018 attojoules.
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