How many foot pound in 1 TeV? The answer is 1.1817053329112E-7. We assume you are converting between foot-pound force and teraelectronvolt. You can view more details on each measurement unit: foot pound or TeV The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot pound, or 6241506.4799632 TeV. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and teraelectronvolts. Type in your own numbers in the form to convert the units!
1 foot pound to TeV = 8462346.51016 TeV
2 foot pound to TeV = 16924693.02032 TeV
3 foot pound to TeV = 25387039.53048 TeV
4 foot pound to TeV = 33849386.04064 TeV
5 foot pound to TeV = 42311732.5508 TeV
6 foot pound to TeV = 50774079.06097 TeV
7 foot pound to TeV = 59236425.57113 TeV
8 foot pound to TeV = 67698772.08129 TeV
9 foot pound to TeV = 76161118.59145 TeV
10 foot pound to TeV = 84623465.10161 TeV
You can do the reverse unit conversion from TeV to foot pound, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "tera" represents a factor of 1012, or in exponential notation, 1E12.
So 1 teraelectronvolt = 1012 .
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