How many dekajoule in 1 foot pounds? The answer is 0.13558179483314. We assume you are converting between dekajoule and foot-pound force. You can view more details on each measurement unit: dekajoule or foot pounds The SI derived unit for energy is the joule. 1 joule is equal to 0.1 dekajoule, or 0.73756214927727 foot pounds. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between dekajoules and foot pounds. Type in your own numbers in the form to convert the units!
1 dekajoule to foot pounds = 7.37562 foot pounds
5 dekajoule to foot pounds = 36.87811 foot pounds
10 dekajoule to foot pounds = 73.75621 foot pounds
15 dekajoule to foot pounds = 110.63432 foot pounds
20 dekajoule to foot pounds = 147.51243 foot pounds
25 dekajoule to foot pounds = 184.39054 foot pounds
30 dekajoule to foot pounds = 221.26864 foot pounds
40 dekajoule to foot pounds = 295.02486 foot pounds
50 dekajoule to foot pounds = 368.78107 foot pounds
You can do the reverse unit conversion from foot pounds to dekajoule, or enter any two units below:
The SI prefix "deka" represents a factor of 101, or in exponential notation, 1E1.
So 1 dekajoule = 101 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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