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How many N-m in 1 foot pound?
The answer is 1.3558179483314.
We assume you are converting between newton-meter and foot-pound force.
You can view more details on each measurement unit:
N-m or foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 1 N-m, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between newton meters and foot pounds.
Type in your own numbers in the form to convert the units!
1 N-m to foot pound = 0.73756 foot pound
5 N-m to foot pound = 3.68781 foot pound
10 N-m to foot pound = 7.37562 foot pound
20 N-m to foot pound = 14.75124 foot pound
30 N-m to foot pound = 22.12686 foot pound
40 N-m to foot pound = 29.50249 foot pound
50 N-m to foot pound = 36.87811 foot pound
75 N-m to foot pound = 55.31716 foot pound
100 N-m to foot pound = 73.75621 foot pound
You can do the reverse unit conversion from foot pound to N-m, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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