Re: Potassium citrate 1620 MHz to mEqs

Re: Potassium citrate 1620 MHz to mEqs   (09/15/2025, 12:56 PM)

1. Determine the molecular weight (MW):

≈ 306 g/mol of potassium citrate (K₃C₆H₅O₇)

Three potassium ions (K⁺) are present in each molecule.

K's atomic weight is 39.1 g/mol.

K total = 3 × 39.1 = 117.3 g/mol

2. K fraction in potassium citrate:

117.3/306≈0.383

3. Determine how much potassium is in 1620 mg of potassium citrate:

1620 × 0.383 ≈ 620 mg of K⁺

4. Convert K⁺ mg to mEq:

mEq = mg / atomic weight × valence

Valence = 1 for K⁺.

620 /39.1 ≈ 15.8 mEq ​

✅ Response: ≈ 15.8 mEq of potassium = 1620 mg potassium citrate.