How many oz-in in 1 foot-pound force?
The answer is 191.99999948048.
We assume you are converting between ounce inch and foot-pound force.
You can view more details on each measurement unit:
oz-in or foot-pound force
The SI derived unit for torque is the newton meter.
1 newton meter is equal to 141.61193227806 oz-in, or 0.73756214927727 foot-pound force.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between ounce inches and foot pounds.
Type in your own numbers in the form to convert the units!
1 oz-in to foot-pound force = 0.00521 foot-pound force
10 oz-in to foot-pound force = 0.05208 foot-pound force
50 oz-in to foot-pound force = 0.26042 foot-pound force
100 oz-in to foot-pound force = 0.52083 foot-pound force
200 oz-in to foot-pound force = 1.04167 foot-pound force
500 oz-in to foot-pound force = 2.60417 foot-pound force
1000 oz-in to foot-pound force = 5.20833 foot-pound force
You can do the reverse unit conversion from foot-pound force to oz-in, or enter any two units below:
oz-in to millinewton-meter
oz-in to newton metre
oz-in to newton-centimeter
oz-in to kilogram-meter
oz-in to micronewton-meter
oz-in to dyne-centimeter
oz-in to gram-centimeter
oz-in to kilonewton-meter
oz-in to pound-inch
oz-in to ton meter
As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.
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