How many newton meter in 1 foot pound?
The answer is 1.3558179483314.
We assume you are converting between newton-meter and foot-pound force.
You can view more details on each measurement unit: newton meter or
foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 1 newton meter, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between newton meters and foot pounds.
Type in your own numbers in the form to convert the units!

››Quick conversion chart of newton meter to foot pound

1 newton meter to foot pound = 0.73756 foot pound

5 newton meter to foot pound = 3.68781 foot pound

10 newton meter to foot pound = 7.37562 foot pound

20 newton meter to foot pound = 14.75124 foot pound

30 newton meter to foot pound = 22.12686 foot pound

40 newton meter to foot pound = 29.50249 foot pound

50 newton meter to foot pound = 36.87811 foot pound

75 newton meter to foot pound = 55.31716 foot pound

100 newton meter to foot pound = 73.75621 foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.

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