How many microsecond in 1 sidereal month?
The answer is 2360591600000.

We assume you are converting between **microsecond** and **sidereal month**.

You can view more details on each measurement unit:

microsecond or
sidereal month

The SI base unit for **time** is the second.

1 second is equal to 1000000 microsecond, or 4.2362262070237E-7 sidereal month.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between microseconds and months.

Type in your own numbers in the form to convert the units!

You may also want to find out how many days
are between two dates on the calendar. Use the
**date calculator**
to get your age in days or measure the duration of an event.

You can do the reverse unit conversion from sidereal month to microsecond, or enter any two units below:

microsecond to day

microsecond to shake

microsecond to year

microsecond to minute

microsecond to fortnight

microsecond to decade

microsecond to century

microsecond to hour

microsecond to second

microsecond to quarter

The SI prefix "micro" represents a factor of
10^{-6}, or in exponential notation, 1E-6.

So 1 microsecond = 10^{-6} arcseconds.

The definition of a second is as follows:

A second of arc or arcsecond is a unit of angular measurement which comprises one-sixtieth of an arcminute, or 1/3600 of a degree of arc or 1/1296000 (approximately 7.7×10-7) of a circle. It is the angular diameter of an object of 1 unit diameter at a distance of 360×60×60/(2pi) (approximately 206,265 units), such as (approximately) 1 cm at 2.1 km, or, directly from the definition, 1 astronomical unit at 1 parsec.

The sidereal month is defined as the Moon's orbital period in a non-rotating frame of reference (which on average is equal to its rotation period in the same frame). It is about 27.32166 days (27 days, 7 hours, 43 minutes, 11.6 seconds). The exact duration of the orbital period cannot be easily determined, because the 'non-rotating frame of reference' cannot be observed directly. However, it is approximately equal to the time it takes the Moon to pass twice a "fixed" star (different stars give different results because all have proper motions and are not really fixed in position).

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