››Convert joule to foot-pound force

 joule foot pound

How many joule in 1 foot pound? The answer is 1.3558179483314.
We assume you are converting between joule and foot-pound force.
You can view more details on each measurement unit:
joule or foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between joules and foot pounds.
Type in your own numbers in the form to convert the units!

››Quick conversion chart of joule to foot pound

1 joule to foot pound = 0.73756 foot pound

5 joule to foot pound = 3.68781 foot pound

10 joule to foot pound = 7.37562 foot pound

20 joule to foot pound = 14.75124 foot pound

30 joule to foot pound = 22.12686 foot pound

40 joule to foot pound = 29.50249 foot pound

50 joule to foot pound = 36.87811 foot pound

75 joule to foot pound = 55.31716 foot pound

100 joule to foot pound = 73.75621 foot pound

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››Definition: Joule

The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).

››Definition: Foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.

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