How many inch pound in 1 dekajoule?
The answer is 88.507461068334.
We assume you are converting between inch-pound and dekajoule.
You can view more details on each measurement unit: inch pound or
dekajoule
The SI derived unit for energy is the joule.
1 joule is equal to 8.8507461068334 inch pound, or 0.1 dekajoule.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between inch pounds and dekajoules.
Type in your own numbers in the form to convert the units!

››Quick conversion chart of inch pound to dekajoule

1 inch pound to dekajoule = 0.0113 dekajoule

10 inch pound to dekajoule = 0.11298 dekajoule

20 inch pound to dekajoule = 0.22597 dekajoule

30 inch pound to dekajoule = 0.33895 dekajoule

40 inch pound to dekajoule = 0.45194 dekajoule

50 inch pound to dekajoule = 0.56492 dekajoule

100 inch pound to dekajoule = 1.12985 dekajoule

200 inch pound to dekajoule = 2.2597 dekajoule

››Want other units?

You can do the reverse unit conversion from
dekajoule to inch pound, or enter any two units below:

The SI prefix "deka" represents a factor of
10^{1}, or in exponential notation, 1E1.

So 1 dekajoule = 10^{1} joules.

The definition of a joule is as follows:

The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).

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