How many foot-pound force in 1 dyne-centimeter? The answer is 7.3756214927727E-8. We assume you are converting between foot-pound force and dyne centimeter. You can view more details on each measurement unit: foot-pound force or dyne-centimeter The SI derived unit for torque is the newton meter. 1 newton meter is equal to 0.73756214927727 foot-pound force, or 10000000 dyne-centimeter. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and dyne centimeters. Type in your own numbers in the form to convert the units!
1 foot-pound force to dyne-centimeter = 13558179.48331 dyne-centimeter
2 foot-pound force to dyne-centimeter = 27116358.96663 dyne-centimeter
3 foot-pound force to dyne-centimeter = 40674538.44994 dyne-centimeter
4 foot-pound force to dyne-centimeter = 54232717.93326 dyne-centimeter
5 foot-pound force to dyne-centimeter = 67790897.41657 dyne-centimeter
6 foot-pound force to dyne-centimeter = 81349076.89988 dyne-centimeter
7 foot-pound force to dyne-centimeter = 94907256.3832 dyne-centimeter
8 foot-pound force to dyne-centimeter = 108465435.86651 dyne-centimeter
9 foot-pound force to dyne-centimeter = 122023615.34983 dyne-centimeter
10 foot-pound force to dyne-centimeter = 135581794.83314 dyne-centimeter
You can do the reverse unit conversion from dyne-centimeter to foot-pound force, or enter any two units below:
As a unit of torque, one foot-pound is the torque created by one pound force acting at a perpendicular distance of one foot from a pivot point.
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