How many foot-pound force in 1 dekajoule? The answer is 7.3756214927727. We assume you are converting between foot-pound force and dekajoule. You can view more details on each measurement unit: foot-pound force or dekajoule The SI derived unit for energy is the joule. 1 joule is equal to 0.73756214927727 foot-pound force, or 0.1 dekajoule. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between foot pounds and dekajoules. Type in your own numbers in the form to convert the units!
1 foot-pound force to dekajoule = 0.13558 dekajoule
5 foot-pound force to dekajoule = 0.67791 dekajoule
10 foot-pound force to dekajoule = 1.35582 dekajoule
20 foot-pound force to dekajoule = 2.71164 dekajoule
30 foot-pound force to dekajoule = 4.06745 dekajoule
40 foot-pound force to dekajoule = 5.42327 dekajoule
50 foot-pound force to dekajoule = 6.77909 dekajoule
75 foot-pound force to dekajoule = 10.16863 dekajoule
100 foot-pound force to dekajoule = 13.55818 dekajoule
You can do the reverse unit conversion from dekajoule to foot-pound force, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "deka" represents a factor of 101, or in exponential notation, 1E1.
So 1 dekajoule = 101 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
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