How many foot pound in 1 kilojoule?
The answer is 737.56214927727.
We assume you are converting between foot-pound force and kilojoule.
You can view more details on each measurement unit: foot pound or
kilojoule
The SI derived unit for energy is the joule.
1 joule is equal to 0.73756214927727 foot pound, or 0.001 kilojoule.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between foot pounds and kilojoules.
Type in your own numbers in the form to convert the units!

››Quick conversion chart of foot pound to kilojoule

1 foot pound to kilojoule = 0.00136 kilojoule

10 foot pound to kilojoule = 0.01356 kilojoule

50 foot pound to kilojoule = 0.06779 kilojoule

100 foot pound to kilojoule = 0.13558 kilojoule

200 foot pound to kilojoule = 0.27116 kilojoule

500 foot pound to kilojoule = 0.67791 kilojoule

1000 foot pound to kilojoule = 1.35582 kilojoule

››Want other units?

You can do the reverse unit conversion from
kilojoule to foot pound, or enter any two units below:

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.

››Definition: Kilojoule

The SI prefix "kilo" represents a factor of
10^{3}, or in exponential notation, 1E3.

So 1 kilojoule = 10^{3} joules.

The definition of a joule is as follows:

The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).

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