How many exaelectronvolt in 1 foot pound? The answer is 8.4623465101609. We assume you are converting between exaelectronvolt and foot-pound force. You can view more details on each measurement unit: exaelectronvolt or foot pound The SI derived unit for energy is the joule. 1 joule is equal to 6.2415064799632 exaelectronvolt, or 0.73756214927727 foot pound. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between exaelectronvolts and foot pounds. Type in your own numbers in the form to convert the units!
1 exaelectronvolt to foot pound = 0.11817 foot pound
5 exaelectronvolt to foot pound = 0.59085 foot pound
10 exaelectronvolt to foot pound = 1.18171 foot pound
20 exaelectronvolt to foot pound = 2.36341 foot pound
30 exaelectronvolt to foot pound = 3.54512 foot pound
40 exaelectronvolt to foot pound = 4.72682 foot pound
50 exaelectronvolt to foot pound = 5.90853 foot pound
75 exaelectronvolt to foot pound = 8.86279 foot pound
100 exaelectronvolt to foot pound = 11.81705 foot pound
You can do the reverse unit conversion from foot pound to exaelectronvolt, or enter any two units below:
The SI prefix "exa" represents a factor of 1018, or in exponential notation, 1E18.
So 1 exaelectronvolt = 1018 .
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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