## Convert electronvolt to foot-pound force

 electronvolt foot pound

How many electronvolt in 1 foot pound? The answer is 8.4623465101609E+18. We assume you are converting between electronvolt and foot-pound force. You can view more details on each measurement unit: electronvolt or foot pound The SI derived unit for energy is the joule. 1 joule is equal to 6.2415064799632E+18 electronvolt, or 0.73756214927727 foot pound. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between electronvolts and foot pounds. Type in your own numbers in the form to convert the units!

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## Definition: Electron volt

In physics, the electron volt (eV) is a unit of energy. By definition, it is equal to the amount of kinetic energy gained by a single unbound electron when it accelerates through an electrostatic potential difference of one volt.

## Definition: Foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.

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