›› Convert electronvolt to foot-pound force


electron volt
foot pound

›› More information from the unit converter

How many electron volt in 1 foot pound? The answer is 8.4623465101609E+18.
We assume you are converting between electronvolt and foot-pound force.
You can view more details on each measurement unit:
electron volt or foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 6.2415064799632E+18 electron volt, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between electronvolts and foot pounds.
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›› Definition: Electron volt

In physics, the electron volt (eV) is a unit of energy. By definition, it is equal to the amount of kinetic energy gained by a single unbound electron when it accelerates through an electrostatic potential difference of one volt.


›› Definition: Foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.


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