How many dekawatt hour in 1 foot pound? The answer is 3.7661609675872E-5. We assume you are converting between dekawatt hour and foot-pound force. You can view more details on each measurement unit: dekawatt hour or foot pound The SI derived unit for energy is the joule. 1 joule is equal to 2.7777777777778E-5 dekawatt hour, or 0.73756214927727 foot pound. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between dekawatt hours and foot pounds. Type in your own numbers in the form to convert the units!
1 dekawatt hour to foot pound = 26552.23737 foot pound
2 dekawatt hour to foot pound = 53104.47475 foot pound
3 dekawatt hour to foot pound = 79656.71212 foot pound
4 dekawatt hour to foot pound = 106208.9495 foot pound
5 dekawatt hour to foot pound = 132761.18687 foot pound
6 dekawatt hour to foot pound = 159313.42424 foot pound
7 dekawatt hour to foot pound = 185865.66162 foot pound
8 dekawatt hour to foot pound = 212417.89899 foot pound
9 dekawatt hour to foot pound = 238970.13637 foot pound
10 dekawatt hour to foot pound = 265522.37374 foot pound
You can do the reverse unit conversion from foot pound to dekawatt hour, or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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