›› Convert decajoule to foot-pound force


decajoule
foot pound


›› More information from the unit converter

How many decajoule in 1 foot pound? The answer is 0.13558179483314.
We assume you are converting between decajoule and foot-pound force.
You can view more details on each measurement unit:
decajoule or foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 0.1 decajoule, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between decajoules and foot pounds.
Type in your own numbers in the form to convert the units!



›› Quick conversion chart of decajoule to foot pound

1 decajoule to foot pound = 7.37562 foot pound

5 decajoule to foot pound = 36.87811 foot pound

10 decajoule to foot pound = 73.75621 foot pound

15 decajoule to foot pound = 110.63432 foot pound

20 decajoule to foot pound = 147.51243 foot pound

25 decajoule to foot pound = 184.39054 foot pound

30 decajoule to foot pound = 221.26864 foot pound

40 decajoule to foot pound = 295.02486 foot pound

50 decajoule to foot pound = 368.78107 foot pound



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›› Definition: Decajoule

The SI prefix "deca" represents a factor of 101, or in exponential notation, 1E1.

So 1 decajoule = 101 joules.

The definition of a joule is as follows:

The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).


›› Definition: Foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.


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