How many centijoule in 1 foot-pound force? The answer is 135.58179483314. We assume you are converting between centijoule and foot-pound force. You can view more details on each measurement unit: centijoule or foot-pound force The SI derived unit for energy is the joule. 1 joule is equal to 100 centijoule, or 0.73756214927727 foot-pound force. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between centijoules and foot pounds. Type in your own numbers in the form to convert the units!
1 centijoule to foot-pound force = 0.00738 foot-pound force
10 centijoule to foot-pound force = 0.07376 foot-pound force
50 centijoule to foot-pound force = 0.36878 foot-pound force
100 centijoule to foot-pound force = 0.73756 foot-pound force
200 centijoule to foot-pound force = 1.47512 foot-pound force
500 centijoule to foot-pound force = 3.68781 foot-pound force
1000 centijoule to foot-pound force = 7.37562 foot-pound force
You can do the reverse unit conversion from foot-pound force to centijoule, or enter any two units below:
The SI prefix "centi" represents a factor of 10-2, or in exponential notation, 1E-2.
So 1 centijoule = 10-2 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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