Convert centijoule to foot-pound force


centijoule
foot pound


More information from the unit converter

How many centijoule in 1 foot pound? The answer is 135.58179483314.
We assume you are converting between centijoule and foot-pound force.
You can view more details on each measurement unit:
centijoule or foot pound
The SI derived unit for energy is the joule.
1 joule is equal to 100 centijoule, or 0.73756214927727 foot pound.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between centijoules and foot pounds.
Type in your own numbers in the form to convert the units!



Quick conversion chart of centijoule to foot pound

1 centijoule to foot pound = 0.00738 foot pound

10 centijoule to foot pound = 0.07376 foot pound

50 centijoule to foot pound = 0.36878 foot pound

100 centijoule to foot pound = 0.73756 foot pound

200 centijoule to foot pound = 1.47512 foot pound

500 centijoule to foot pound = 3.68781 foot pound

1000 centijoule to foot pound = 7.37562 foot pound



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Definition: Centijoule

The SI prefix "centi" represents a factor of 10-2, or in exponential notation, 1E-2.

So 1 centijoule = 10-2 joules.

The definition of a joule is as follows:

The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).


Definition: Foot pound

In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.


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