Did you mean to convert | calorie [15 °C] calorie [I.T.] calorie [nutritional] calorie [thermochemical] |
to | foot-pound force |
How many calories in 1 foot pound? The answer is 0.32390891784877. We assume you are converting between calorie [15 °C] and foot-pound force. You can view more details on each measurement unit: calories or foot pound The SI derived unit for energy is the joule. 1 joule is equal to 0.23890295761862 calories, or 0.73756214927727 foot pound. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between calories and foot pounds. Type in your own numbers in the form to convert the units!
1 calories to foot pound = 3.08729 foot pound
5 calories to foot pound = 15.43644 foot pound
10 calories to foot pound = 30.87288 foot pound
15 calories to foot pound = 46.30931 foot pound
20 calories to foot pound = 61.74575 foot pound
25 calories to foot pound = 77.18219 foot pound
30 calories to foot pound = 92.61863 foot pound
40 calories to foot pound = 123.49151 foot pound
50 calories to foot pound = 154.36438 foot pound
You can do the reverse unit conversion from foot pound to calories, or enter any two units below:
15 °C calorie: the amount of energy required to warm 1 g of air-free water from 14.5 °C to 15.5 °C at a constant pressure of 101.325 kPa (1 atm). Experimental values of this calorie ranged from 4.1852 J to 4.1858 J. The CIPM in 1950 published a mean experimental value of 4.1855 J, noting an uncertainty of 0.0005 J.
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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