Convert calorie [15 °C] to millimeter kilogram-force


calorie
millimeter kilogram-force


Did you mean to convert calorie [15 °C]
calorie [I.T.]
calorie [nutritional]
calorie [thermochemical]
to millimeter kilogram-force

More information from the unit converter

How many calorie in 1 millimeter kilogram-force? The answer is 0.0023428376893306. We assume you are converting between calorie [15 °C] and millimeter kilogram-force. You can view more details on each measurement unit: calorie or millimeter kilogram-force The SI derived unit for energy is the joule. 1 joule is equal to 0.23890295761862 calorie, or 101.97162129779 millimeter kilogram-force. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between calories and millimeter kilogram-force. Type in your own numbers in the form to convert the units!



Quick conversion chart of calorie to millimeter kilogram-force

1 calorie to millimeter kilogram-force = 426.83281 millimeter kilogram-force

2 calorie to millimeter kilogram-force = 853.66562 millimeter kilogram-force

3 calorie to millimeter kilogram-force = 1280.49844 millimeter kilogram-force

4 calorie to millimeter kilogram-force = 1707.33125 millimeter kilogram-force

5 calorie to millimeter kilogram-force = 2134.16406 millimeter kilogram-force

6 calorie to millimeter kilogram-force = 2560.99687 millimeter kilogram-force

7 calorie to millimeter kilogram-force = 2987.82969 millimeter kilogram-force

8 calorie to millimeter kilogram-force = 3414.6625 millimeter kilogram-force

9 calorie to millimeter kilogram-force = 3841.49531 millimeter kilogram-force

10 calorie to millimeter kilogram-force = 4268.32812 millimeter kilogram-force


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Common energy conversions


Definition: Calorie

15 °C calorie: the amount of energy required to warm 1 g of air-free water from 14.5 °C to 15.5 °C at a constant pressure of 101.325 kPa (1 atm). Experimental values of this calorie ranged from 4.1852 J to 4.1858 J. The CIPM in 1950 published a mean experimental value of 4.1855 J, noting an uncertainty of 0.0005 J.


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