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How many anomalistic year in 1 mo? The answer is 0.083329423785551. We assume you are converting between anomalistic year and Gregorian month. You can view more details on each measurement unit: anomalistic year or mo The SI base unit for time is the second. 1 second is equal to 3.1687251843163E-8 anomalistic year, or 3.8026486208174E-7 mo. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between years and months. Type in your own numbers in the form to convert the units!
You may also want to find out how many days are between two dates on the calendar. Use the date calculatorto get your age in days or measure the duration of an event.
1 anomalistic year to mo = 12.00056 mo
2 anomalistic year to mo = 24.00113 mo
3 anomalistic year to mo = 36.00169 mo
4 anomalistic year to mo = 48.00225 mo
5 anomalistic year to mo = 60.00282 mo
6 anomalistic year to mo = 72.00338 mo
7 anomalistic year to mo = 84.00394 mo
8 anomalistic year to mo = 96.0045 mo
9 anomalistic year to mo = 108.00507 mo
10 anomalistic year to mo = 120.00563 mo
You can do the reverse unit conversion from mo to anomalistic year, or enter any two units below:
The anomalistic year is the time taken for the Earth to complete one revolution with respect to its apsides. The orbit of the Earth is elliptical; the extreme points, called apsides, are the perihelion, where the Earth is closest to the Sun (January 3 in 2011), and the aphelion, where the Earth is farthest from the Sun (July 4 in 2011). The anomalistic year is usually defined as the time between perihelion passages. Its average duration is 365.259636 days (365 d 6 h 13 min 52.6 s) (at the epoch J2011.0).
The month is a unit of time, used with calendars, which is approximately as long as some natural period related to the motion of the Moon (i.e. "Moonth"). The mean month length of the Gregorian calendar is 30.436875 days.
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