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3x+3y-1=0x-3y+2=05x+5y-3=0none of these

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<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_CG_C02_E07_017_S01.png" width="80%"> <br> The family of line through the given lines is <br> `L-=x-7y+5+lambda(x+3y-2)=0 " " (1)` <br> For line L=0 in the diagram, the distance of any point say (2,0) on the line x+3y-2=0 from the line x-7y+5=0 and the line L=0 must be the same. Therefore, <br> `|(2+5)/(sqrt(50))| = |(2+2lambda+5-2lambda)/(sqrt((1+lambda)^(2) + (3lambda-7)^(2)))|` <br> `"or " 10lambda^(2)-40lambda = 0` <br> `"i.e., " lambda = 4 or 0` <br> `"Hence, "L=0, lambda = 4` <br> Therefore, the required line is 5x+5y-3=0.