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foot [pre-1963 Canada]
How many foot [pre-1963 Canada] in 1 smoot? The answer is 5.2363076923077. We assume you are converting between foot [pre-1963 Canada] and smoot. You can view more details on each measurement unit: foot [pre-1963 Canada] or smoot The SI base unit for length is the metre. 1 metre is equal to 3.0769230769231 foot [pre-1963 Canada], or 0.58761311552474 smoot. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between feet [pre-1963 Canada] and smoots. Type in your own numbers in the form to convert the units!
1 foot [pre-1963 Canada] to smoot = 0.19097 smoot
5 foot [pre-1963 Canada] to smoot = 0.95487 smoot
10 foot [pre-1963 Canada] to smoot = 1.90974 smoot
20 foot [pre-1963 Canada] to smoot = 3.81949 smoot
30 foot [pre-1963 Canada] to smoot = 5.72923 smoot
40 foot [pre-1963 Canada] to smoot = 7.63897 smoot
50 foot [pre-1963 Canada] to smoot = 9.54871 smoot
75 foot [pre-1963 Canada] to smoot = 14.32307 smoot
100 foot [pre-1963 Canada] to smoot = 19.09743 smoot
You can do the reverse unit conversion from smoot to foot [pre-1963 Canada], or enter any two units below:
A smoot is a unit of distance (or "length", as physical scientists say) used for measuring the Harvard Bridge. It is named after an MIT fraternity pledge at Lambda Chi Alpha fraternity, Oliver R. Smoot (class of 1962). In October of 1958, fellow students helped Mr. Smoot measure the length of the bridge by placing him end to end and marking the increments. Oliver was a top student at MIT and went on to run NIST, the National Institute of Standards and Technology. The smoot is equal to his height (five feet and seven inches -- 1.70 m), and the bridge's length was measured to be "364.4 smoots plus one ear".
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