How many pounds in 1 dekagram-force?
The answer is 0.0220462262941.

We assume you are converting between **pound-force** and **dekagram-force**.

You can view more details on each measurement unit:

pounds or
dekagram-force

The SI derived unit for **force** is the newton.

1 newton is equal to 0.224808943871 pounds, or 10.1971621298 dekagram-force.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between pounds-force and dekagrams-force.

Type in your own numbers in the form to convert the units!

The pound-force is a non-SI unit of force or weight (properly abbreviated "lbf" or "lbf"). The pound-force is equal to a mass of one pound multiplied by the standard acceleration due to gravity on Earth (which is defined as exactly 9.806 65 m/sē, or exactly 196,133/6096 ft/sē, or approximately 32.174 05 ft/sē).

The SI prefix "deka" represents a factor of
10^{1}, or in exponential notation, 1E1.

So 1 dekagram-force = 10^{1} gram-force.

**ConvertUnits.com** provides an online
conversion calculator for all types of measurement units.
You can find metric conversion tables for SI units, as well
as English units, currency, and other data. Type in unit
symbols, abbreviations, or full names for units of length,
area, mass, pressure, and other types. Examples include mm,
inch, 100 kg, US fluid ounce, 6'3", 10 stone 4, cubic cm,
metres squared, grams, moles, feet per second, and many more!

This page was loaded in 0.0029 seconds.