How many foot-pound force in 1 petajoule?
The answer is 7.37562149277E+14.
We assume you are converting between foot-pound force and petajoule.
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foot-pound force or petajoule
The SI derived unit for energy is the joule.
1 joule is equal to 0.737562149277 foot-pound force, or 1.0E-15 petajoule.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between foot pounds and petajoules.
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In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
The SI prefix "peta" represents a factor of 1015, or in exponential notation, 1E15.
So 1 petajoule = 1015 joules.
The definition of a joule is as follows:
The joule (symbol J, also called newton meter, watt second, or coulomb volt) is the SI unit of energy and work. The unit is pronounced to rhyme with "tool", and is named in honor of the physicist James Prescott Joule (1818-1889).
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